A photograph has a length that is 2 inches longer than it’s width, x. So it’s area is given by the expression x(x+2) square inches. If the area of the photograph is 48 square inches, what is the width of the photograph
Accepted Solution
A:
The equation will look something like this:x(x+2) = 48Distribute the x:x^2 + 2x = 48Subtract both sides by 48:x^2 + 2x - 48 = 0(x+8)(x-6) = 0x = -8 and x = 6Since you can't have a negative width, the only plausible answer is 6 inches.