What would be the first and last terms of the polynomial if it was rewritten in standard form? Answer these quickly without performing all of the indicated operations: (a)- (2x^3 − x^2 − 9x +7) +(11x^2 − 6x^3+ 2x − 9) (b)- (x − 3)(2x +3)(x − 1) (c)- (2x − 3)(3x+ 5) − (x +1)(2x^2 − 6x+ 3)

Answer:(a) So first term will be [tex]-4x^3\ and\ last\ term\ will\ be -2[/tex]    (b) So first term will be [tex]2x^3\ and\ last\ term\ will\ be\ 9[/tex](c)  So first term will be [tex]-2x^3\ and\ last\ term\ will\ be -12[/tex]Step-by-step explanation:We have to find the first and last term of the expression (a) We have given expression [tex](2x^3-x^2-9x+7)+(11x^2-6x^3+2x-9)[/tex]After addition it will be [tex]-4x^3+10x^2-7x-2[/tex]So first term will be [tex]-4x^3\ and\ last\ term\ will\ be -2[/tex](b) We have given equation [tex](x-3)(2x+3)(x-1)[/tex]After multiplication it will be [tex]2x^3-5x^2-12x+9[/tex]So first term will be [tex]2x^3\ and\ last\ term\ will\ be\ 9[/tex](c) We have given expression [tex](2x-3)(3x+5)-(x+1)(2x^2-6x+3)[/tex]It can be written as [tex]6x^2+x-15-(2x^3-4x^2-3x-3)[/tex][tex]6x^2+x-15-(2x^3-4x^2-3x-3)=-2x^3+10x^2+4x-12[/tex]So first term will be [tex]-2x^3\ and\ last\ term\ will\ be -12[/tex]