In what quadrant is the center of the following equation located: (x - 4)^2+ (y + 5)^2 = 16? Write 1, 2, 3, or 4. 25 POINTS!!!!!!!!!!!!!BRAINLIESTNEED ANSWER NOW!!!!!
Accepted Solution
A:
Answer:Quadrant 4Step-by-step explanation:The equation of a circle in standard form is(x - h)² + (y - k)² = r²where (h, k) are the coordinates of the centre and r is the radius(x - 4)² + (y + 5)² = 16 ← equation of circle in standard formwith centre (h, k) = (4, - 5) ← Quadrant 4